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X^2+2(X-1)X+(X+5)=0
We multiply parentheses
X^2+2X^2-2X+(X+5)=0
We get rid of parentheses
X^2+2X^2-2X+X+5=0
We add all the numbers together, and all the variables
3X^2-1X+5=0
a = 3; b = -1; c = +5;
Δ = b2-4ac
Δ = -12-4·3·5
Δ = -59
Delta is less than zero, so there is no solution for the equation
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